From: "Mike Wise" Sent: Friday, May 05, 2000 11:46 AM > Would I be correct to assume that phosphoric acid would be > more effective at lowering pH because it releases 3 H+ ions > for every PO4 -3 ion in solution? The advantage to phosphoric acid is its buffering point - for practical purposes laying between that of peat and carbonates. The downside is the build-up of phosphates in the closed tank environment - how do you like your algae? As weak polyprotic acids step through the ionization process, the corresponding ionization constants grow ever smaller. This usually produces at least an order or two of *magnitude*'s difference in the ratios, so even though releases three times as many hydrogen ions the additional gain is statistically insignificant. In the case of H3PO4, the constants are K1=7.5 x 10-3, K2=6.3 x 10-8, and K3=3.6 x 10-13 - so you can see the overall gain is puny, indeed. (As a plus, these large differences make for more stable buffering compounds.) Compare hydrochloric to sulfuric, a much stronger diprotic. As sulfuric ionizes to sulfurous acid, the intermediate acid is almost as strong to ionize as the original. For practical purposes again, having the two ionization constants so closely "in synch" does double the amount of hydrogen produced. And the added SO4 ions only affect the hardness without feeding any unwanteds... -Y- David A. Youngker nestor10@mindspring.com ...who apparently is far more sleepless than Bob D. tonight... ------------------------------------------------------------------------- This is the apistogramma mailing list, apisto@listbox.com. For instructions on how to subscribe or unsubscribe or get help, email apisto-request@listbox.com. Search http://altavista.digital.com for "Apistogramma Mailing List Archives"!